Alexander ZVEREV breezes past Christopher O'CONNELL into Indian Wells third round

Alexander Zverev (No. 6) made a successful debut at Indian Wells against Christopher O’Connell (No. 66) with a score of 6-4, 6-4.

The 6th seed had no issues against the Australian and advanced to the tournament's third round, where he will face the winner between his compatriot Yannick Hangmann and the 27th seed Tallon Griekspoor.

In a match that lasted nearly two hours, Zverev seized crucial moments to take the lead and comfortably secure the victory.

The Australian displayed a solid performance, holding his serve for much of the first set. However, with the score at 5-4 in favor of Zverev, he played an erratic service game, ultimately giving the break to his opponent, who claimed the set 6-4.

In the second set, O’Connell showed an improved level in his returns and created some challenging moments for Zverev. He had several break opportunities but was unable to capitalize on them. Despite the pressure, 'Sascha' closed out the match with a 6-4, 6-4 scoreline, marking a return to success after his disappointing exit in the Mexican Open, where he was eliminated in the first round.