Jasmine
Paolini achieved a significant victory over
Elena Rybakina at the
WTA Finals.
The Italian made a successful debut by defeating the 2022 Wimbledon champion
7-6, 6-4.
Rybakina, on the other hand, showed moments of strong tennis despite
a long period without competition, but struggled to maintain consistency
throughout the match, with unforced errors ultimately costing her.
Consistent Paolini outshines Rybakina
Despite
being over two months out of competition, Rybakina showed no signs of it early
on. She won 7 of her first 8 service points, including two aces, making it
clear that breaking her serve would not be easy for the Italian.
Still, with
limited match play, it became challenging for Rybakina to maintain her level, and by
the 6th game, she faced her first break, allowing Paolini to go ahead 4-2. The
lead didn’t last long, as Rybakina took advantage of her second break point to
quickly level the set at 4-4. As the games progressed, errors appeared on both
sides, with Rybakina particularly struggling with her forehand, although her
backhand allowed her to dictate the match’s pace.
The set
parity led to a tiebreak, where Paolini held a 6-2 advantage, ultimately
securing the set 7-6(5) after missing three set points. Rybakina played a more
aggressive game, hitting 17 winners compared to Paolini’s 4, though her 36
unforced errors—against Paolini’s 16—proved costly.
The second
set started on a fresh note for Rybakina, who raised her first serve percentage
from 44% to over 65%. However, Paolini seemed to increasingly find her rhythm.
Both players saved break points early in the set, but as it developed,
Rybakina’s unforced errors resurfaced, leading to a break in the 7th game.
The Italian
made no mistakes on her serve and ultimately sealed the win 7-6(5), 6-4,
leaving her in a strong position in the group. Both players will return to the
court on Monday for crucial Round Robin matches. Rybakina will face a tough
challenge against world No. 1
Aryna Sabalenka, while Paolini will take on
Olympic gold medalist
Zheng Qinwen.