Alexander Zverev defeated Miomir Kecmanovic in the quarter-finals of the Chengdu Open, winning the match 5-7, 7-5, 6-2.

The World No. 10 made a strong start at the ATP 250 event yesterday when he showed resilience and determination to overcome an on-form Pavel Kotov in three sets. Today, Zverev faced World No. 47 Kecmanovic.

Before this match, their head-to-head was level at 1-1. The Serbian player was the tournament's seventh seed and had ousted Benjamin Lock and Corentin Moutet in straight sets to reach the quarter-final. In this match, he was aiming to end a losing streak against Top 10 players in the ATP Ranking.

The battle was a close-knit one from the start, with the players holding their service games to keep it even. Both Zverev and Kecmanovic had a chance for a break in the first two games of the match but neither managed to secure the crucial point.

However, after securing a tiebreak at least in the first set, Kecmanovic managed to get ahead of his opponent as an unforced error from Zverev gave the Serbian set point, which he won to take the first set 7-5.

Despite this, Zverev did not let the frustration get the better of him and came back fighting in the second set. At 1-1, he made a breakthrough by securing the break after Kecmanovic hit the ball out.

Zverev carried this momentum on into the final set, breaking his opponent in the very first game. Nevertheless, Kecmanovic was still working hard, playing some impressive drop shots and redirecting his backhand to keep himself in the set.

However, Zverev held firm and secured himself the double break after Kecmanovic failed to get the ball back across the net on a crucial point. In the final game, the points went to deuce before the 26-year-old pulled off an impressive forehand winner to get match point.

Zverev will progress through to the semi-finals of the Chengdu Open.